(4/3)(x+1)=-4

Solution for (4/3)(x+1)=-4 equation:

(4/3)(x+1)=-4

We move all terms to the left:

(4/3)(x+1)-(-4)=0


Domain of the equation: 3)(x+1)!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)(x+1)-(-4)=0

We add all the numbers together, and all the variables

(+4/3)(x+1)+4=0

We multiply parentheses ..

(+4x^2+4/3*1)+4=0

We multiply all the terms by the denominator


(+4x^2+4+4*3*1)=0

We get rid of parentheses

4x^2+4+4*3*1=0

We add all the numbers together, and all the variables

4x^2+16=0

a = 4; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·4·16
Δ = -256
Delta is less than zero, so there is no solution for the equation