(3/10)(x+1)=-4

Solution for (3/10)(x+1)=-4 equation:

(3/10)(x+1)=-4

We move all terms to the left:

(3/10)(x+1)-(-4)=0


Domain of the equation: 10)(x+1)!=0

x∈R


We add all the numbers together, and all the variables

(+3/10)(x+1)-(-4)=0

We add all the numbers together, and all the variables

(+3/10)(x+1)+4=0

We multiply parentheses ..

(+3x^2+3/10*1)+4=0

We multiply all the terms by the denominator


(+3x^2+3+4*10*1)=0

We get rid of parentheses

3x^2+3+4*10*1=0

We add all the numbers together, and all the variables

3x^2+43=0

a = 3; b = 0; c = +43;
Δ = b2-4ac
Δ = 02-4·3·43
Δ = -516
Delta is less than zero, so there is no solution for the equation