(4+x)(2x-22)=0

Solution for (4+x)(2x-22)=0 equation:

(4+x)(2x-22)=0

We add all the numbers together, and all the variables

(x+4)(2x-22)=0

We multiply parentheses ..

(+2x^2-22x+8x-88)=0

We get rid of parentheses

2x^2-22x+8x-88=0

We add all the numbers together, and all the variables

2x^2-14x-88=0

a = 2; b = -14; c = -88;
Δ = b2-4ac
Δ = -142-4·2·(-88)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-30}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+30}{2*2}=\frac{44}{4}
=11
$