(9X/5)+32=x

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Solution for (9X/5)+32=x equation: 



(9X/5)+32=X

We move all terms to the left:

(9X/5)+32-(X)=0

We add all the numbers together, and all the variables

(+9X/5)-X+32=0

We add all the numbers together, and all the variables

-1X+(+9X/5)+32=0

We get rid of parentheses

-1X+9X/5+32=0

We multiply all the terms by the denominator


-1X*5+9X+32*5=0

We add all the numbers together, and all the variables

9X-1X*5+160=0

Wy multiply elements

9X-5X+160=0

We add all the numbers together, and all the variables

4X+160=0

We move all terms containing X to the left, all other terms to the right

4X=-160

X=-160/4

X=-40

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