(4+2i)-(3-5i)=0

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Solution for (4+2i)-(3-5i)=0 equation: 



(4+2i)-(3-5i)=0

We add all the numbers together, and all the variables

(2i+4)-(-5i+3)=0

We get rid of parentheses

2i+5i+4-3=0

We add all the numbers together, and all the variables

7i+1=0

We move all terms containing i to the left, all other terms to the right

7i=-1

i=-1/7

i=-1/7

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