(4+2d)/(4(d-8)(d-8))=7/16

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Solution for (4+2d)/(4(d-8)(d-8))=7/16 equation: 



(4+2d)/(4(d-8)(d-8))=7/16

We move all terms to the left:

(4+2d)/(4(d-8)(d-8))-(7/16)=0



Domain of the equation: (4(d-8)(d-8))!=0

d∈R



We add all the numbers together, and all the variables

(2d+4)/(4(d-8)(d-8))-(+7/16)=0

We get rid of parentheses

(2d+4)/(4(d-8)(d-8))-7/16=0

We multiply parentheses ..

(2d+4)/(4(+d^2-8d-8d+64))-7/16=0

We calculate fractions


(32d+64)/((4(+d^2-8d-8d+64))*16)+(-7*(4(+d^2-8d-8d+64)))/((4(+d^2-8d-8d+64))*16)=0



We calculate terms in parentheses: +(32d+64)/((4(+d^2-8d-8d+64))*16), so:

32d+64)/((4(+d^2-8d-8d+64))*16

determiningTheFunctionDomain
64)/((4(+d^2-8d-8d+64))*16+32d

We multiply all the terms by the denominator


64)+32d*((4(+d^2-8d-8d+64))*16

Back to the equation:

+(64)+32d*((4(+d^2-8d-8d+64))*16)





We calculate terms in parentheses: +(-7*(4(+d^2-8d-8d+64)))/((4(+d^2-8d-8d+64))*16), so:

-7*(4(+d^2-8d-8d+64)))/((4(+d^2-8d-8d+64))*16

We multiply all the terms by the denominator


-7*(4(+d^2-8d-8d+64)))

Back to the equation:

+(-7*(4(+d^2-8d-8d+64))))

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