-3=-15-2c(c-1)-3c

Solution for -3=-15-2c(c-1)-3c equation:

-3=-15-2c(c-1)-3c

We move all terms to the left:

-3-(-15-2c(c-1)-3c)=0


We calculate terms in parentheses: -(-15-2c(c-1)-3c), so:

-15-2c(c-1)-3c

determiningTheFunctionDomain
-2c(c-1)-3c-15

We add all the numbers together, and all the variables

-3c-2c(c-1)-15

We multiply parentheses

-2c^2-3c+2c-15

We add all the numbers together, and all the variables

-2c^2-1c-15

Back to the equation:

-(-2c^2-1c-15)


We get rid of parentheses

2c^2+1c+15-3=0

We add all the numbers together, and all the variables

2c^2+c+12=0

a = 2; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·2·12
Δ = -95
Delta is less than zero, so there is no solution for the equation