-(2n-6)=2(n+3)

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Solution for -(2n-6)=2(n+3) equation: 



-(2n-6)=2(n+3)

We move all terms to the left:

-(2n-6)-(2(n+3))=0

We get rid of parentheses

-2n-(2(n+3))+6=0



We calculate terms in parentheses: -(2(n+3)), so:

2(n+3)

We multiply parentheses

2n+6

Back to the equation:

-(2n+6)



We get rid of parentheses

-2n-2n-6+6=0

We add all the numbers together, and all the variables

-4n=0

n=0/-4

n=0

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