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(4)/(5)b=12
We move all terms to the left:
(4)/(5)b-(12)=0
Domain of the equation: 5b!=0We multiply all the terms by the denominator
b!=0/5
b!=0
b∈R
-12*5b+4=0
Wy multiply elements
-60b+4=0
We move all terms containing b to the left, all other terms to the right
-60b=-4
b=-4/-60
b=1/15
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