3(t-3)+7t=9t-2

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Solution for 3(t-3)+7t=9t-2 equation: 



3(t-3)+7t=9t-2

We move all terms to the left:

3(t-3)+7t-(9t-2)=0

We add all the numbers together, and all the variables

7t+3(t-3)-(9t-2)=0

We multiply parentheses

7t+3t-(9t-2)-9=0

We get rid of parentheses

7t+3t-9t+2-9=0

We add all the numbers together, and all the variables

t-7=0

We move all terms containing t to the left, all other terms to the right

t=7

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