(x+3)(x+3+5)=(x+2)(x+2+8)

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Solution for (x+3)(x+3+5)=(x+2)(x+2+8) equation: 



(x+3)(x+3+5)=(x+2)(x+2+8)

We move all terms to the left:

(x+3)(x+3+5)-((x+2)(x+2+8))=0

We add all the numbers together, and all the variables

(x+3)(x+8)-((x+2)(x+10))=0

We multiply parentheses ..

(+x^2+8x+3x+24)-((x+2)(x+10))=0



We calculate terms in parentheses: -((x+2)(x+10)), so:

(x+2)(x+10)

We multiply parentheses ..

(+x^2+10x+2x+20)

We get rid of parentheses

x^2+10x+2x+20

We add all the numbers together, and all the variables

x^2+12x+20

Back to the equation:

-(x^2+12x+20)



We get rid of parentheses

x^2-x^2+8x+3x-12x+24-20=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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