If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x-4)(2x+17)=180
We move all terms to the left:
(3x-4)(2x+17)-(180)=0
We multiply parentheses ..
(+6x^2+51x-8x-68)-180=0
We get rid of parentheses
6x^2+51x-8x-68-180=0
We add all the numbers together, and all the variables
6x^2+43x-248=0
a = 6; b = 43; c = -248;
Δ = b2-4ac
Δ = 432-4·6·(-248)
Δ = 7801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{7801}}{2*6}=\frac{-43-\sqrt{7801}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{7801}}{2*6}=\frac{-43+\sqrt{7801}}{12} $
| 1/9(3y-6)=-1/3(4-2y | | 9+w/5=15 | | 48-7y=8 | | (7x+3)=(3x+15)+(2x+18) | | 3n+46=-1+8n | | -0.2x-0.3x=15 | | 3f+5=2 | | -5(3x-8)=100 | | 4x–7=7x-61 | | 2.1n=63 | | 130=3x+5 | | 8r-15=3r | | -6-6(2n-4)=78 | | 5-2h=21 | | 40=1/2(12h) | | a–7=12, | | 130r=520 | | k^2=k=20 | | 0.9a-2.6=1.7 | | 2(3x+4)-(x-3)=41 | | 4(h+2)=-20 | | 16x-9=-61 | | -2y+(-2)=11 | | (x-10)(x-10)=x2-20x+ | | (3x-4)+(2x+17)=180 | | -14x+3x+6x+5=180 | | -1/4(-1-20x)=5x-2 | | 3x+80=2x+20 | | 30=-4/15a+7 | | 14=12-y | | –7x+5–2x=–40 | | -213=p-187 |