(x-10)(x-10)=x2-20x+

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Solution for (x-10)(x-10)=x2-20x+ equation:



(x-10)(x-10)=x2-20x+
We move all terms to the left:
(x-10)(x-10)-(x2-20x+)=0
We add all the numbers together, and all the variables
-(+x^2-20x+)+(x-10)(x-10)=0
We get rid of parentheses
-x^2+20x+(x-10)(x-10)-=0
We multiply parentheses ..
-x^2+(+x^2-10x-10x+100)+20x-=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-10x-10x+100)+20x=0
We get rid of parentheses
-1x^2+x^2-10x-10x+20x+100=0
We add all the numbers together, and all the variables
100!=0
There is no solution for this equation

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