(x+3)+3(x-1)=2

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Solution for (x+3)+3(x-1)=2 equation: 



(x+3)+3(x-1)=2

We move all terms to the left:

(x+3)+3(x-1)-(2)=0

We multiply parentheses

(x+3)+3x-3-2=0

We get rid of parentheses

x+3x+3-3-2=0

We add all the numbers together, and all the variables

4x-2=0

We move all terms containing x to the left, all other terms to the right

4x=2

x=2/4

x=1/2

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