1/9(3y-6)=-1/3(4-2y

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Solution for 1/9(3y-6)=-1/3(4-2y equation: 



1/9(3y-6)=-1/3(4-2y

We move all terms to the left:

1/9(3y-6)-(-1/3(4-2y)=0



Domain of the equation: 9(3y-6)!=0

y∈R





Domain of the equation: 3(4-2y)!=0

y∈R



We add all the numbers together, and all the variables

1/9(3y-6)-(-1/3(-2y+4)=0

We calculate fractions


(3y(-)/(9(3y-6)*3(-2y+4))+(-(-9y3)/(9(3y-6)*3(-2y+4))=0



We calculate terms in parentheses: +(3y(-)/(9(3y-6)*3(-2y+4))+(-(-9y3)/(9(3y-6)*3(-2y+4)), so:

3y(-)/(9(3y-6)*3(-2y+4))+(-(-9y3)/(9(3y-6)*3(-2y+4)

We add all the numbers together, and all the variables

(-(-9y^3)/(9(3y-6)*3(-2y+4)+3y0/(9(3y-6)*3(-2y+4))

We can not solve this equation

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