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(3x-3)+(2x+1)=(5x-2)-(2x+1)
We move all terms to the left:
(3x-3)+(2x+1)-((5x-2)-(2x+1))=0
We get rid of parentheses
3x+2x-((5x-2)-(2x+1))-3+1=0
We calculate terms in parentheses: -((5x-2)-(2x+1)), so:We add all the numbers together, and all the variables
(5x-2)-(2x+1)
We get rid of parentheses
5x-2x-2-1
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
5x-(3x-3)-2=0
We get rid of parentheses
5x-3x+3-2=0
We add all the numbers together, and all the variables
2x+1=0
We move all terms containing x to the left, all other terms to the right
2x=-1
x=-1/2
x=-1/2
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