3(2x+4)-(3x-5)=4(x+3)

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Solution for 3(2x+4)-(3x-5)=4(x+3) equation: 



3(2x+4)-(3x-5)=4(x+3)

We move all terms to the left:

3(2x+4)-(3x-5)-(4(x+3))=0

We multiply parentheses

6x-(3x-5)-(4(x+3))+12=0

We get rid of parentheses

6x-3x-(4(x+3))+5+12=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

3x-(4x+12)+17=0

We get rid of parentheses

3x-4x-12+17=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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