6(3g-2)=2(2g+1)

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Solution for 6(3g-2)=2(2g+1) equation: 



6(3g-2)=2(2g+1)

We move all terms to the left:

6(3g-2)-(2(2g+1))=0

We multiply parentheses

18g-(2(2g+1))-12=0



We calculate terms in parentheses: -(2(2g+1)), so:

2(2g+1)

We multiply parentheses

4g+2

Back to the equation:

-(4g+2)



We get rid of parentheses

18g-4g-2-12=0

We add all the numbers together, and all the variables

14g-14=0

We move all terms containing g to the left, all other terms to the right

14g=14

g=14/14

g=1

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