(3x-2)/5=(x-9)/2

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Solution for (3x-2)/5=(x-9)/2 equation: 



(3x-2)/5=(x-9)/2

We move all terms to the left:

(3x-2)/5-((x-9)/2)=0

We calculate fractions


3x/()+(-((x-9)*5)/()=0



We calculate terms in parentheses: +(-((x-9)*5)/(), so:

-((x-9)*5)/(

We multiply all the terms by the denominator


-((x-9)*5)



We calculate terms in parentheses: -((x-9)*5), so:

(x-9)*5

We multiply parentheses

5x-45

Back to the equation:

-(5x-45)



We get rid of parentheses

-5x+45

Back to the equation:

+(-5x+45)



We get rid of parentheses

3x/()-5x+45=0

We multiply all the terms by the denominator


3x-5x*()+45*()=0

We add all the numbers together, and all the variables

3x-5x*()=0

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