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(3/2)x+3=5x+1-1
We move all terms to the left:
(3/2)x+3-(5x+1-1)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/2)x-(+5x)+3=0
We multiply parentheses
3x^2-(+5x)+3=0
We get rid of parentheses
3x^2-5x+3=0
a = 3; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·3·3
Δ = -11
Delta is less than zero, so there is no solution for the equation
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