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(3x-15)+(x+40)+(2x-5)=x
We move all terms to the left:
(3x-15)+(x+40)+(2x-5)-(x)=0
We add all the numbers together, and all the variables
-1x+(3x-15)+(x+40)+(2x-5)=0
We get rid of parentheses
-1x+3x+x+2x-15+40-5=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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