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(3x-14)(2x=15)=(x-7)
We move all terms to the left:
(3x-14)(2x-(15))=0
We multiply parentheses ..
(+6x^2-45x-28x+210)=0
We get rid of parentheses
6x^2-45x-28x+210=0
We add all the numbers together, and all the variables
6x^2-73x+210=0
a = 6; b = -73; c = +210;
Δ = b2-4ac
Δ = -732-4·6·210
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-17}{2*6}=\frac{56}{12} =4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+17}{2*6}=\frac{90}{12} =7+1/2 $
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