2(4z+3)-8=64

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Solution for 2(4z+3)-8=64 equation: 



2(4z+3)-8=64

We move all terms to the left:

2(4z+3)-8-(64)=0

We add all the numbers together, and all the variables

2(4z+3)-72=0

We multiply parentheses

8z+6-72=0

We add all the numbers together, and all the variables

8z-66=0

We move all terms containing z to the left, all other terms to the right

8z=66

z=66/8

z=8+1/4

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