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(3x-1)(2x-9)=90
We move all terms to the left:
(3x-1)(2x-9)-(90)=0
We multiply parentheses ..
(+6x^2-27x-2x+9)-90=0
We get rid of parentheses
6x^2-27x-2x+9-90=0
We add all the numbers together, and all the variables
6x^2-29x-81=0
a = 6; b = -29; c = -81;
Δ = b2-4ac
Δ = -292-4·6·(-81)
Δ = 2785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{2785}}{2*6}=\frac{29-\sqrt{2785}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{2785}}{2*6}=\frac{29+\sqrt{2785}}{12} $
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