10+0.5(c-12)=11

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Solution for 10+0.5(c-12)=11 equation: 



10+0.5(c-12)=11

We move all terms to the left:

10+0.5(c-12)-(11)=0

We add all the numbers together, and all the variables

0.5(c-12)-1=0

We multiply parentheses

0.5c-6-1=0

We add all the numbers together, and all the variables

0.5c-7=0

We move all terms containing c to the left, all other terms to the right

0.5c=7

c=7/0.5

c=14

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