6912=(18x+6x)*18x

Solution for 6912=(18x+6x)*18x equation:

6912=(18x+6x)*18x

We move all terms to the left:

6912-((18x+6x)*18x)=0

We add all the numbers together, and all the variables

-((+24x)*18x)+6912=0


We calculate terms in parentheses: -((+24x)*18x), so:

(+24x)*18x

We multiply parentheses

432x^2

Back to the equation:

-(432x^2)


a = -432; b = 0; c = +6912;
Δ = b2-4ac
Δ = 02-4·(-432)·6912
Δ = 11943936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11943936}=3456$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3456}{2*-432}=\frac{-3456}{-864}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3456}{2*-432}=\frac{3456}{-864}
=-4
$