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(3x+7)(7x-9)=0
We multiply parentheses ..
(+21x^2-27x+49x-63)=0
We get rid of parentheses
21x^2-27x+49x-63=0
We add all the numbers together, and all the variables
21x^2+22x-63=0
a = 21; b = 22; c = -63;
Δ = b2-4ac
Δ = 222-4·21·(-63)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-76}{2*21}=\frac{-98}{42} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+76}{2*21}=\frac{54}{42} =1+2/7 $
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