-8b(8b+5)-2=27+5b

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Solution for -8b(8b+5)-2=27+5b equation:



-8b(8b+5)-2=27+5b
We move all terms to the left:
-8b(8b+5)-2-(27+5b)=0
We add all the numbers together, and all the variables
-8b(8b+5)-(5b+27)-2=0
We multiply parentheses
-64b^2-40b-(5b+27)-2=0
We get rid of parentheses
-64b^2-40b-5b-27-2=0
We add all the numbers together, and all the variables
-64b^2-45b-29=0
a = -64; b = -45; c = -29;
Δ = b2-4ac
Δ = -452-4·(-64)·(-29)
Δ = -5399
Delta is less than zero, so there is no solution for the equation

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