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(3x+7)(6x+20)=90
We move all terms to the left:
(3x+7)(6x+20)-(90)=0
We multiply parentheses ..
(+18x^2+60x+42x+140)-90=0
We get rid of parentheses
18x^2+60x+42x+140-90=0
We add all the numbers together, and all the variables
18x^2+102x+50=0
a = 18; b = 102; c = +50;
Δ = b2-4ac
Δ = 1022-4·18·50
Δ = 6804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6804}=\sqrt{324*21}=\sqrt{324}*\sqrt{21}=18\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-18\sqrt{21}}{2*18}=\frac{-102-18\sqrt{21}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+18\sqrt{21}}{2*18}=\frac{-102+18\sqrt{21}}{36} $
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