19=(10x/9)+x

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Solution for 19=(10x/9)+x equation: 



19=(10x/9)+x

We move all terms to the left:

19-((10x/9)+x)=0



Domain of the equation: 9)+x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+10x/9)+x)+19=0

We multiply all the terms by the denominator


-((+10x+19*9)+x)=0



We calculate terms in parentheses: -((+10x+19*9)+x), so:

(+10x+19*9)+x

We add all the numbers together, and all the variables

(10x+171)+x

We add all the numbers together, and all the variables

x+(10x+171)

We get rid of parentheses

x+10x+171

We add all the numbers together, and all the variables

11x+171

Back to the equation:

-(11x+171)



We get rid of parentheses

-11x-171=0

We move all terms containing x to the left, all other terms to the right

-11x=171

x=171/-11

x=-15+6/11

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