2(3t-3)=6(t-1/3)

Solution for 2(3t-3)=6(t-1/3) equation:

2(3t-3)=6(t-1/3)

We move all terms to the left:

2(3t-3)-(6(t-1/3))=0

We add all the numbers together, and all the variables

2(3t-3)-(6(+t-1/3))=0

We multiply parentheses

6t-(6(+t-1/3))-6=0

We multiply all the terms by the denominator


6t*3))-(6(+t-1-6*3))=0

We add all the numbers together, and all the variables

6t*3))-(6(t-19))=0

We add all the numbers together, and all the variables

6t*3))-(6(t=0

Wy multiply elements

18t^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{36}=0$