27=3c-3(c-2c)

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Solution for 27=3c-3(c-2c) equation: 



27=3c-3(c-2c)

We move all terms to the left:

27-(3c-3(c-2c))=0

We add all the numbers together, and all the variables

-(3c-3(-1c))+27=0



We calculate terms in parentheses: -(3c-3(-1c)), so:

3c-3(-1c)

We multiply parentheses

3c+3c

We add all the numbers together, and all the variables

6c

Back to the equation:

-(6c)



We move all terms containing c to the left, all other terms to the right

-6c=-27

c=-27/-6

c=4+1/2

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