(3x+5)+(2x+1)+(3x+5)+(2x+1)=98

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Solution for (3x+5)+(2x+1)+(3x+5)+(2x+1)=98 equation: 



(3x+5)+(2x+1)+(3x+5)+(2x+1)=98

We move all terms to the left:

(3x+5)+(2x+1)+(3x+5)+(2x+1)-(98)=0

We get rid of parentheses

3x+2x+3x+2x+5+1+5+1-98=0

We add all the numbers together, and all the variables

10x-86=0

We move all terms containing x to the left, all other terms to the right

10x=86

x=86/10

x=8+3/5

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