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1/8(a+3)=1/5(9-a)
We move all terms to the left:
1/8(a+3)-(1/5(9-a))=0
Domain of the equation: 8(a+3)!=0
a∈R
Domain of the equation: 5(9-a))!=0We add all the numbers together, and all the variables
a∈R
1/8(a+3)-(1/5(-1a+9))=0
We calculate fractions
(5a(-)/(8(a+3)*5(-1a+9)))+(-8aa/(8(a+3)*5(-1a+9)))=0
We calculate terms in parentheses: +(5a(-)/(8(a+3)*5(-1a+9))), so:
5a(-)/(8(a+3)*5(-1a+9))
We add all the numbers together, and all the variables
5a0/(8(a+3)*5(-1a+9))
We multiply all the terms by the denominator
5a0
We add all the numbers together, and all the variables
5a
Back to the equation:
+(5a)
We calculate terms in parentheses: +(-8aa/(8(a+3)*5(-1a+9))), so:We get rid of parentheses
-8aa/(8(a+3)*5(-1a+9))
We multiply all the terms by the denominator
-8aa
Back to the equation:
+(-8aa)
5a-8aa=0
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