(4v-7)(2+v)=0

Solution for (4v-7)(2+v)=0 equation:

(4v-7)(2+v)=0

We add all the numbers together, and all the variables

(4v-7)(v+2)=0

We multiply parentheses ..

(+4v^2+8v-7v-14)=0

We get rid of parentheses

4v^2+8v-7v-14=0

We add all the numbers together, and all the variables

4v^2+v-14=0

a = 4; b = 1; c = -14;
Δ = b2-4ac
Δ = 12-4·4·(-14)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*4}=\frac{-16}{8}
=-2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*4}=\frac{14}{8}
=1+3/4
$