(3x+4)+(5x)+(2x+8)=32

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Solution for (3x+4)+(5x)+(2x+8)=32 equation: 



(3x+4)+(5x)+(2x+8)=32

We move all terms to the left:

(3x+4)+(5x)+(2x+8)-(32)=0

We add all the numbers together, and all the variables

5x+(3x+4)+(2x+8)-32=0

We get rid of parentheses

5x+3x+2x+4+8-32=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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