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(3x+3)/(x-3)=5
We move all terms to the left:
(3x+3)/(x-3)-(5)=0
Domain of the equation: (x-3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=3
x∈R
(3x+3)-5*(x-3)=0
We multiply parentheses
(3x+3)-5x+15=0
We get rid of parentheses
3x-5x+3+15=0
We add all the numbers together, and all the variables
-2x+18=0
We move all terms containing x to the left, all other terms to the right
-2x=-18
x=-18/-2
x=+9
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