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3x+3/x-3=5
We move all terms to the left:
3x+3/x-3-(5)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3x+3/x-8=0
We multiply all the terms by the denominator
3x*x-8*x+3=0
We add all the numbers together, and all the variables
-8x+3x*x+3=0
Wy multiply elements
3x^2-8x+3=0
a = 3; b = -8; c = +3;
Δ = b2-4ac
Δ = -82-4·3·3
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{7}}{2*3}=\frac{8-2\sqrt{7}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{7}}{2*3}=\frac{8+2\sqrt{7}}{6} $
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