(3x+4)(x-3)=3x2

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Solution for (3x+4)(x-3)=3x2 equation: 



(3x+4)(x-3)=3x^2

We move all terms to the left:

(3x+4)(x-3)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+(3x+4)(x-3)=0

We multiply parentheses ..

-3x^2+(+3x^2-9x+4x-12)=0

We get rid of parentheses

-3x^2+3x^2-9x+4x-12=0

We add all the numbers together, and all the variables

-5x-12=0

We move all terms containing x to the left, all other terms to the right

-5x=12

x=12/-5

x=-2+2/5

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