2(x-3)=3(6-x)+1

Solution for 2(x-3)=3(6-x)+1 equation:

2(x-3)=3(6-x)+1

We move all terms to the left:

2(x-3)-(3(6-x)+1)=0

We add all the numbers together, and all the variables

2(x-3)-(3(-1x+6)+1)=0

We multiply parentheses

2x-(3(-1x+6)+1)-6=0


We calculate terms in parentheses: -(3(-1x+6)+1), so:

3(-1x+6)+1

We multiply parentheses

-3x+18+1

We add all the numbers together, and all the variables

-3x+19

Back to the equation:

-(-3x+19)


We get rid of parentheses

2x+3x-19-6=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5