4(x+1)+9=2(x+3)-5

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Solution for 4(x+1)+9=2(x+3)-5 equation: 



4(x+1)+9=2(x+3)-5

We move all terms to the left:

4(x+1)+9-(2(x+3)-5)=0

We multiply parentheses

4x-(2(x+3)-5)+4+9=0



We calculate terms in parentheses: -(2(x+3)-5), so:

2(x+3)-5

We multiply parentheses

2x+6-5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

4x-(2x+1)+13=0

We get rid of parentheses

4x-2x-1+13=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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