(3x+3)+(3x+2)+(3x)=(3x)+(3x)+(4x+1)

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Solution for (3x+3)+(3x+2)+(3x)=(3x)+(3x)+(4x+1) equation: 



(3x+3)+(3x+2)+(3x)=(3x)+(3x)+(4x+1)

We move all terms to the left:

(3x+3)+(3x+2)+(3x)-((3x)+(3x)+(4x+1))=0

We add all the numbers together, and all the variables

3x+(3x+3)+(3x+2)-(3x+3x+(4x+1))=0

We get rid of parentheses

3x+3x+3x-(3x+3x+(4x+1))+3+2=0



We calculate terms in parentheses: -(3x+3x+(4x+1)), so:

3x+3x+(4x+1)

We add all the numbers together, and all the variables

6x+(4x+1)

We get rid of parentheses

6x+4x+1

We add all the numbers together, and all the variables

10x+1

Back to the equation:

-(10x+1)



We add all the numbers together, and all the variables

9x-(10x+1)+5=0

We get rid of parentheses

9x-10x-1+5=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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