2(6x+3)=-6(x+1)

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Solution for 2(6x+3)=-6(x+1) equation:



2(6x+3)=-6(x+1)
We move all terms to the left:
2(6x+3)-(-6(x+1))=0
We multiply parentheses
12x-(-6(x+1))+6=0
We calculate terms in parentheses: -(-6(x+1)), so:
-6(x+1)
We multiply parentheses
-6x-6
Back to the equation:
-(-6x-6)
We get rid of parentheses
12x+6x+6+6=0
We add all the numbers together, and all the variables
18x+12=0
We move all terms containing x to the left, all other terms to the right
18x=-12
x=-12/18
x=-2/3

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