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12v^2+86v+14=0
a = 12; b = 86; c = +14;
Δ = b2-4ac
Δ = 862-4·12·14
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-82}{2*12}=\frac{-168}{24} =-7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+82}{2*12}=\frac{-4}{24} =-1/6 $
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