8x+1=2(4x-3)+7

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Solution for 8x+1=2(4x-3)+7 equation: 



8x+1=2(4x-3)+7

We move all terms to the left:

8x+1-(2(4x-3)+7)=0



We calculate terms in parentheses: -(2(4x-3)+7), so:

2(4x-3)+7

We multiply parentheses

8x-6+7

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We get rid of parentheses

8x-8x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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