6(v+3)=-2(7v-5)+8v

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Solution for 6(v+3)=-2(7v-5)+8v equation:



6(v+3)=-2(7v-5)+8v
We move all terms to the left:
6(v+3)-(-2(7v-5)+8v)=0
We multiply parentheses
6v-(-2(7v-5)+8v)+18=0
We calculate terms in parentheses: -(-2(7v-5)+8v), so:
-2(7v-5)+8v
We add all the numbers together, and all the variables
8v-2(7v-5)
We multiply parentheses
8v-14v+10
We add all the numbers together, and all the variables
-6v+10
Back to the equation:
-(-6v+10)
We get rid of parentheses
6v+6v-10+18=0
We add all the numbers together, and all the variables
12v+8=0
We move all terms containing v to the left, all other terms to the right
12v=-8
v=-8/12
v=-2/3

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