(3x+25)=(2x+58)

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Solution for (3x+25)=(2x+58) equation: 



(3x+25)=(2x+58)

We move all terms to the left:

(3x+25)-((2x+58))=0

We get rid of parentheses

3x-((2x+58))+25=0



We calculate terms in parentheses: -((2x+58)), so:

(2x+58)

We get rid of parentheses

2x+58

Back to the equation:

-(2x+58)



We get rid of parentheses

3x-2x-58+25=0

We add all the numbers together, and all the variables

x-33=0

We move all terms containing x to the left, all other terms to the right

x=33

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