(3x+21)(3x+21)=0

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Solution for (3x+21)(3x+21)=0 equation: 



(3x+21)(3x+21)=0

We multiply parentheses ..

(+9x^2+63x+63x+441)=0

We get rid of parentheses

9x^2+63x+63x+441=0

We add all the numbers together, and all the variables

9x^2+126x+441=0

a = 9; b = 126; c = +441;
Δ = b2-4ac
Δ = 1262-4·9·441
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-126}{18}=-7$

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