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(52-2x)(16-2x)=160
We move all terms to the left:
(52-2x)(16-2x)-(160)=0
We add all the numbers together, and all the variables
(-2x+52)(-2x+16)-160=0
We multiply parentheses ..
(+4x^2-32x-104x+832)-160=0
We get rid of parentheses
4x^2-32x-104x+832-160=0
We add all the numbers together, and all the variables
4x^2-136x+672=0
a = 4; b = -136; c = +672;
Δ = b2-4ac
Δ = -1362-4·4·672
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-88}{2*4}=\frac{48}{8} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+88}{2*4}=\frac{224}{8} =28 $
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