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3=2/(v-4)
We move all terms to the left:
3-(2/(v-4))=0
Domain of the equation: (v-4))!=0We multiply all the terms by the denominator
v∈R
-(2+3*(v-4))=0
We calculate terms in parentheses: -(2+3*(v-4)), so:We get rid of parentheses
2+3*(v-4)
determiningTheFunctionDomain 3*(v-4)+2
We multiply parentheses
3v-12+2
We add all the numbers together, and all the variables
3v-10
Back to the equation:
-(3v-10)
-3v+10=0
We move all terms containing v to the left, all other terms to the right
-3v=-10
v=-10/-3
v=3+1/3
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